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400x-3x^2=10000
We move all terms to the left:
400x-3x^2-(10000)=0
a = -3; b = 400; c = -10000;
Δ = b2-4ac
Δ = 4002-4·(-3)·(-10000)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-200}{2*-3}=\frac{-600}{-6} =+100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+200}{2*-3}=\frac{-200}{-6} =33+1/3 $
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